Ashtabula County Maps
Ashtabula County occupies the northeast corner of the State of Ohio, and of the Western Reserve. Its territorial limits embrace both land and water. The land portion is bounded on the north by Lake Erie, on the south by the county of Trumbull, on the east by the northwestern part of Pennsylvania, and on the west by the northern part of Geauga county, by Lake county, and by the waters of Lake Erie.
Its capital town is Jefferson, which is situated in the eleventh township of the third range, and is in latitude 41° 45′ north, and in longitude 80° 45′ 5″ west. Its entire territory embraces a total area of nine hundred and seven square miles, two hundred and twenty of which are water. The land portion, in reference to which, as disunited from the water of the lake, it is more properly considered when regarding it as an organized county, contains an area of six hundred and eighty-seven square miles, and is larger, by about fifteen square miles, than any other county in the State. – History of Ashtabula County, Ohio by Williams, W. W. Pub. 1878
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Page Created August 2022